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b&mrydkBwb
tReq -- l(1
'
l'2
x
U(lrs)
For
S,,,
at
50
l1z
?,0
0,9
0,85
0,ij
0,7
1FC5
506(4
pole)
to
LRS
for
450C,
=
0.8, a
three-phase,
squi
rrel
-cage
1.he
iol lowinq
technical data
:
4ooc
)
lstart/1ll
=
6.5 (as
per
VDE
output)
20
101
501
100
1
1501
2001
100
500
1000
1500
2
000
2500
I2
15
13
?I
22
23
For
s;;eed
at
50
llz
reV//
Inl
ll
3Q00
15
00
1000
75A
600
500
z
m1n
,')
00
00
00
00
?0
0i)
0
e
;
3
?
9
7
6
6
f
3
I
I
r."qluLl.,r,
To an unloaded synchronous al
ternator
1470 kVA, 450
V,
60
llz,
power
factor
tnduction motoli
s
svritched.on,
rvi
lh
130
kfl
(to
LRS
450C),
140
kil
(t-o
Vot
44- C,
60
Hz, P.
f.
N
=
0,87
=
95'!
Powcr
[actor (startinq)
=
P.f.
sLart
The
rated current
for
the ntotor
is
:
222
A
tl
V3 x
"nrot
x
P.l.ll
xn
1.13x440x0.8/x0.95
The trans
j
ent startj
rrg
current
I tfirl
1U'- INv iN:'-"
= )21 A
t
6.5 =
lzlr]4
A
If
the alternator rated voltage
differs
front that-
0f
lhe motor,
the
startin!
current rlust
be converted
1
-
I
Uel
-
Id44 A
{
LU
lU
U
r,r._
,.
llnrrro
lhp qt)ri.r-
-n'.,or.
f
0r
tr.C
ffil
=vnt
al terna
lor
i
s
SzLr
=VI*
UGun
*
lzu =
1
/3
x
450
x
1477
=
1150
x
103
VA
=
lt50
kVA
l,lhi
ch
gi
ves
:
q
-zu
1I50
kVA
e- . iq(irrl tr =
u.
t.tz
(1550
kVA
=
out-put
of
alternator
to
VDE 40oC)
-N
Thus,
at
power
fact0r
0,5
and pov/er
factor
zero the voltage drop
is
:
AU =
T5%
-4
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