Calibrating The Scales - KEENCUT OVAL 6 Bedienungshandbuch

4.4
Small variations in cut dimensions can occur dependant upon the size and proportion of
the oval, in most cases the error is insignificant but care needs to be used when cutting
ovals below 10 cm [4"]. If in doubt check before cutting and correct as follows:-
Metric
For this example say an 8cm wide by 11cm long
oval is required:-
1. Set the width to say 1cm less than the
finished mat size ie. 7cm
2. Set the differential to the same dimension
as for the finished mat ie. 11cm-8cm. = 3cm.
3. Cut the oval in the normal way.
4. Measure the width of the oval, let us say
it is 7.2cm for example.
5. Compare the 7.2cm with the dimension
read on the width scale.
6. Slide the width scale (Not the cutting head)
until it reads 7.2cm.
7. Measure the length of the oval, let us say
it is 11.3cm, and calculate the difference
between it and the width measured
previously ie. 11.3cm-7.2cm = 3.1cm.
8. To correct the differential scale loosen
the two screws and the knob, swing the
scale until it reads 3.1cm, re-tighten the
screws and the knob.
9. Reset the machine to width = 8cm.
& difference = 3cm. Then cut the
finished oval.
Operation

Calibrating the scales

For this example say a 3" wide by 4" long oval
is required:-
1. Set the width to say
2. Set the differential to the same dimension
3. Cut the oval in the normal way.
4. Measure the width of the oval, let us say
5. Compare the 3
6. Slide the width scale (Not the cutting head)
7. Measure the length of the oval, let us say
8. To correct the differential scale loosen
9. Reset the machine to width = 3". &
Imperial
1
/
2
1
finished mat size ie. 2
as for the finished mat ie. 4" - 3". = 1".
1
it is 3 / " for example.
16
1
/ " with the dimension
16
read on the width scale.
1
until it reads 3 / "
16
it is 4 ", and calculate the difference
between it and the width measured
1
previously ie. 4 " - 3 /
the two screws and the knob, swing the
1
scale until it reads 1 /
16
screws and the knob.
difference = 1" then cut the finished oval.
4.4
" less than the
/ "
2
1
" = 1 / "
16 16
", re-tighten the