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Cleaning The Flue; Calculation Of The Thermal Power - Nordica inserto 70 Gebrauchsanleitung

Crystal angolo
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INSERTO 70 CRYSTAL ANGOLO

12.3. CLEANING THE FLUE

The correct lighting phase, the use of proper quantities and types of fuels, the correct position of the secondary air regulator, enough
draught of the chimney-flue and the presence of combustion air are the essential elements for the optimal functioning of the appliance.
The device should be completely cleaned at least once a year or every time it is needed (in case of bad working and low yield). An
excessive deposit of soot can cause problems in the discharge of smokes and fire in the flue.
The cleaning must be carried out exclusively with cold equipment. This operation should be carried out by a chimney sweeper who
can simultaneously perform an audit of the flue (checking of possible deposits).
Excessive incrustation deposits on the inner walls of the hearth considerably reduce the efficiency of heat exchange; therefore, remove
these deposits using a steel brush whenever necessary. Never use corrosive substances that can damage the thermo-fireplace and
the boiler.
During the cleaning, it is necessary to remove the ash drawer, the grating, and the smoke deflectors from the device in order to ease the
fall of the soot. The deflectors can be easily extracted from their seats since they are not fastened using screws. Once the clearing has
been carried out, place them back in their seats
CAUTION: The lack of the deflectors causes a strong depression, with a too fast combustion, an excessive consumption of wood
with related overheating of the device.

13. CALCULATION OF THE THERMAL POWER

There is not an absolute rule for calculating the correct necessary power. This power is given according to the space to be heated, but it
depends also largely on the insulation. On an average, the calorific value necessary for a properly insulated room is 30 kcal/h per m
an external temperature of 0°C).
Given that 1 kW corresponds to 860 kcal/h, it is possible to adopt a value of 38 W/m
Let's suppose one wishes to heat a room of 150 m
x 38 W/m
= 5700 W or 5,7 kW. As main heating, a 8 kW device is therefore sufficient.
3
Fuel
Dry wood (15% humidity)
Wet wood (50% humidity)
Wood briquettes
Brown coal briquettes
Normal anthracite
Coke
Natural gas
Naphtha
Electricity
6096705 - IT-EN-DE-FR
(Picture 11 at page
43).
(10 x 6 x 2.5 m) in an insulated apartment. In this case, it is necessary to have 150 m
3
Approximate combustion value
Unit
kcal/h
kg
3600
kg
1850
kg
4000
kg
4800
kg
7700
kg
6780
m
7800
3
L
8500
kW/h
860
.
3
Required quantity in relation to 1 kg of dry
kW
4.2
2.2
5.0
5.6
8.9
7.9
9.1
9.9
1.0
(for
3
3
wood
1,00
1,95
0,84
0,75
0,47
0,53
0,46
0,42
4,19
21

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