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6.3 Durchführung von Hyperbel- und Areafunktionen
Beispiel
sinh3,6 =
cosh1,23 =
tanh2,5 =
cosh1,5 – sinh1,5 =
-1
sinh
30 =
-1
cosh
(20÷15) =
-1
x = (tanh
0,88) ÷ 4 =
-1
-1
sinh
2 x cosh
1,5 =
sinh
-1
(2/3) + tanh
-1
erforderliche Eingaben:
3[.]6 [hyp] [sin]
1[.]23 [hyp] [cos]
2[.]5 [hyp] [tan]
1[.]5 [hyp] [cos] [-] [(] 1[.]5
[hyp] [sin] [)] [=]
30 [hyp] [2ndF] [sin
[(] 20 [÷] 15 [)] [hyp] [2ndF]
-1
[cos
]
0[.]88 [hyp] [2ndF] [tan
4 [=]
2 [hyp] [2ndF] [sin
1[.]5 [hyp] [2ndF] [cos
(4/5) =
[(] 2 [÷] 3 [)] [hyp] [2ndF]
-1
[sin
] [+] [(] 4 [÷] 5 [)] [hyp]
[2ndF] [tan
-1
]
-1
] [÷]
-1
] 2 [x] [(]
-1
] [)][=]
-1
] [=]
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18.28545536
1.856761057
0.986614298
0.22313016
4.094622224
0.795365461
0.343941914
1.389388923
1.723757406
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