Palmer-Bowlus (D/2) Kanal
P40= 10
Q[m
/s]= f(h1/P41)*P41
3
bei h1[m]= h+(P41/10)
P41 [m]
Palmer-Bowlus (D/3) Kanal
P40= 11
Q[m
3
/s]= f(h1/P41)*P41
bei h1[m]= h+(P41/10)
P41 [m]
Palmer-Bowlus (rechteckiger) Kanal
P40= 12
Q[m
/s]= C*P42*h
3
1,5
bei C= f(P41/P42)
P41 [m], P42 [m]
46/60 BKI 03 ATEX 027X sea3802n0600p_03
,
2,5
2,5
,
,
D
P41
D/10
D
P41
D/10
P42
D
P41
D/10
P04
P46
h
P04
P46
h
P04
P46
h